Tension Test of Mild Steel Speceiman Lab Report CE 212
1. OBJECTIVES
-To determine the mechanical
properties of steel specimen.
-To perform the tensile test of
mild steel.
-To observe the tensile strength
of different steel grades.
-To study the failure pattern of
different steel grades.
-To compare the performances
different steel grades.
2. ASTM REFERENCE
ASTM E 8 Standard Test Methods for
Tension Testing of Metallic Materials
3. SIGNIFICANCE
This experiment provides fundamental knowledge on
tension behaviour of materials specially mild steel,
test procedure, universal
testing machine and its working
principal, tension specimens,
failure patterns etc.
4. APPARATUS
AND MACHINE
UTM, stop watch, digital slide
calipers and computer.
5. SPECIMEN
Mild steel specimens (40, 60,
and 72.5 grades) of 16 mm diameter.
6. THEORY
Elasticity & Plasticity: When external forces are applied on a body,
made of engineering materials, the external forces tend to deform the body
while the molecular forces acting between the molecules offer resistance
against deformation or displacement of the particles continues till full
resistance to the external forces is setup. If
the forces are now gradually diminished, the body will return, wholly
or partly to its original
shape. Elasticity is the property by virtue of which a material
deformed under the load is enabled to return to its original dimension when the
load is removed. If a body regains
completely its original shape, it is said to perfectly elastic.
Plasticity is the converse of elasticity. A material in plastic state is permanently deformed by the application of load, and it has no tendency to recover. Every elastic material possesses the property of plasticity. Under the action of large forces, most engineering materials become plastic and behave in a manner similar to a viscous liquid. The characteristic of the material by which it undergoes inelastic strains beyond those at the elastic limit is known as plasticity. When large deformations occur in a ductile material loaded in the plastic region, the material is aid to undergo plastic flow
Proportional Limit (Point A): It is the limiting value of the
stress upto which stress is proportional to strain.
Elastic Limit (Point
B): This is the limiting
value of stress upto which if the material is stressed
and then released (unloaded), strain disappears completely the original length
is regained. Its determination, experimentally, is extremely difficult, and
therefore its exact location on the stress-strain diagram is usually not known,
even though it is generally higher than the proportional limit.
Permanent set/permanent deformation: If the load exceeds the elastic limit before it is removed, the material does not fully
regain its initial dimensions. In such
a case the material is said to experience a permanent deformation.
Elastic
Recovery: The recovered deformation after removal of load.
Yield stress (Point C and D): Soon after the stress the elastic
limit, low carbon steel attains it yield point stress. The yield point of a
material is defined as that unit stress that will cause an increase in
deformation without an increase in load. Upon the arrival of yield point, a
ductile material such as low carbon steel stretches an almost unbelievable
amount, frequently 10%of the original length. When the yield stress is reached
elongation takes place more rapidly as
plastic flow takes place over and atoms move into new positions and a
return to the original shape of the test piece is impossible.
Upper Yield Point (Point C): This is the stress at which the load
starts reducing and the extension.
Lower Yield Point
(Point D): At this stage the stress
remains same but strain increases for some time.
The upper yield point is influenced considerably by the shape of the test
specimen, speed of testing, accuracy of alignment , the condition of the test
piece (especially the presence of residual stresses in a test on the full cross
section) and by the testing machines itself and is sometimes completely
suppressed. The lower yield points much less sensitive and is considered to be
more representative.
Yield Strength by Offset Method: For materials having a
stress-strain diagram such as shown in figure (those that do not exhibit a
well-defined yield point) a value of stress, known as the yield strength for
the material, is defined as one producing a certain amount of permanent strain.
Ultimate Strength/Tensile Strength (Point E): This is the maximum
stress the material can resist. The ultimate strength represents the ordinate
to the highest point in the stress-strain diagram and is equal to the maximum
load carried by the specimen divided by the original cross-sectional area.
Breaking Strength/Fracture Strength/Rupture Strength (Point F):
The stress at which finally the specimen fails is called breaking point. It is
the engineering stress at which specimen fracture and complete separation of
the specimen parts occurs.
Strain Hardening/Work Hardening: If a ductile material can be
stressed considerable beyond the yield point without failure,
it is said to strain
harden (When a material deformed
plasticity, it work hardens, that is, the stress has to be increased to
give further deformation).
Necking: After reducing the maximum stress, a localized reduction
in area, called necking, begins, and elongation continues with diminishing load
until the specimen breaks.
Modulus of Rigidity (G): It is defined as the ratio of shearing stress to
shearing strain within elastic limit.
Modulus of Resilience: The work done on a unit volume of material, as a
simple tensile force is gradually increased from zero to such a value that the
proportional limit of the material is reached, is defined as the modulus of
resilience.
Modulus of Rupture/ Modulus of Toughness: The work done on a unit volume
of material as a simple tensile force is gradually increased from zero to the
value causing rupture is defined as the modulus of toughness.
Various machine and structure components are subjected to tensile loading
in numerous applications. For safe design
of these components, their ultimate tensile
strength and ductilityto be determined before actual use. A material when subjected to a tensile
load resists the applied
load by developing internal resisting force. These resistances come due to
atomic bonding between atoms of the material. The resisting force for unit
normal cross-section area is known
as stress.
The value of stress in material goes on increasing
with an increase in applied tensile load, but it has a certain maximum (finite)
limit too. The minimum stress, at which a material fails, is called ultimate
tensile strength.
The end of elastic limit is indicated by the yield
point (load). This can be seen during experiment as explained later in procedure with increase in loading beyond
elastic limit, initial
cross-section area (Ai)
goes on decreasing and finally reduces to its minimum value when the specimen
breaks. Some typical mechanical properties of mild steel are as follows:
Proportional Limit, p = 30~65 ksi (larger for stronger
specimens) Yield
Strength, y =
35~75 ksi (larger for stronger specimens) Ultimate Strength, ult = 60~100 ksi (larger for stronger specimens)
Modulus of Elasticity, E = 29000~30000 ksi (almost uniform for all
types of specimens)
Poisson’s Ratio,
ν = 0.20~0.30 ksi (larger for stronger specimens) Modulus of Resilience =
0.02~0.07 ksi (larger for stronger specimens) Modulus of Toughness = 7~15 ksi
(smaller for stronger specimens) Ductility = 10~35% (smaller for stronger
specimens)
Reduction of Area = 20~60%
(smaller for stronger specimens)
1. PROCEDURE
i)
Measure the diameter of the specimen by slide calipers. Record gage length.
ii)
Fix the specimen in proper position and apply the load
iii) Record the maximum load and
apply load till the breakage.
iv)
Remove the broken specimen and measure the smallest
cross-sectional area and the final length between the gage marks by fitting the
two ends of the broken pieces together.
v)
Note the characteristics of the fractured surface.
2. SAMPLE CALCULATIONS
Initial length of specimen, hi = Final length of specimen, hf = Initial diameter of specimen, di= Final diameter of specimen, df= Initial cross-section area, Ai = Final cross-section area, Af=
1. Draw stress-strain curve in tension.
and Modulus of Resilience in
tension
3. Determine ultimate (max.)
tensile strength from graph
4. Determine yield stress from graph
5. Determine percentage elongation
in length (or height) of the specimen
6. Determine EMF (elongation at
maximum force) from graph
7.
Also determine proportional limit (σp), elastic limit ( σE), yield point ( σy), ultimate load (
σu), breaking strength ( σb), etc.
10.
DATA TABLE
Deformation rate= |
mm/min, Grade= |
|
ksi, Brand= |
|
|||
Time (s) |
Load (N) |
Time (s) |
Load (N) |
Time (s) |
Load (N) |
Time (s) |
Load (N) |
0 |
|
470 |
|
560 |
|
740 |
|
10 |
|
480 |
|
570 |
|
750 |
|
20 |
|
490 |
|
580 |
|
760 |
|
30 |
|
500 |
|
590 |
|
770 |
|
40 |
|
510 |
|
600 |
|
780 |
|
50 |
|
520 |
|
610 |
|
790 |
|
60 |
|
530 |
|
620 |
|
800 |
|
70 |
|
540 |
|
630 |
|
810 |
|
80 |
|
550 |
|
640 |
|
820 |
|
90 |
|
560 |
|
650 |
|
830 |
|
100 |
|
570 |
|
660 |
|
840 |
|
110 |
|
580 |
|
670 |
|
850 |
|
120 |
|
590 |
|
680 |
|
860 |
|
130 |
|
600 |
|
690 |
|
870 |
|
140 |
|
610 |
|
700 |
|
880 |
|
150 |
|
620 |
|
710 |
|
890 |
|
160 |
|
630 |
|
720 |
|
900 |
|
170 |
|
640 |
|
730 |
|
910 |
|
180 |
|
650 |
|
740 |
|
920 |
|
190 |
|
660 |
|
750 |
|
930 |
|
200 |
|
670 |
|
760 |
|
940 |
|
210 |
|
680 |
|
770 |
|
950 |
|
220 |
|
690 |
|
780 |
|
960 |
|
230 |
|
700 |
|
790 |
|
970 |
|
240 |
|
710 |
|
800 |
|
980 |
|
250 |
|
720 |
|
810 |
|
990 |
|
260 |
|
730 |
|
820 |
|
740 |
|
270 |
|
740 |
|
830 |
|
750 |
|
280 |
|
750 |
|
840 |
|
760 |
|
290 |
|
760 |
|
560 |
|
770 |
|
300 |
|
770 |
|
570 |
|
780 |
|
310 |
|
780 |
|
580 |
|
790 |
|
320 |
|
790 |
|
590 |
|
800 |
|
330 |
|
800 |
|
600 |
|
810 |
|
340 |
|
810 |
|
610 |
|
820 |
|
350 |
|
820 |
|
620 |
|
830 |
|
360 |
|
830 |
|
630 |
|
840 |
|
370 |
|
840 |
|
640 |
|
850 |
|
380 |
|
470 |
|
650 |
|
860 |
|
390 |
|
480 |
|
660 |
|
870 |
|
400 |
|
490 |
|
670 |
|
880 |
|
410 |
|
500 |
|
680 |
|
890 |
|
420 |
|
510 |
|
690 |
|
900 |
|
430 |
|
520 |
|
700 |
|
910 |
|
440 |
|
530 |
|
710 |
|
920 |
|
450 |
|
540 |
|
720 |
|
930 |
|
460 |
|
550 |
|
730 |
|
940 |
|
11.
GRAPH
1.
Tensile stress vs. strain curve of 40 Grade bar.
2. Tensile stress vs. strain
curve of 60 Grade bar.
3. Tensile stress vs. strain
curve of 72.5 Grade bar.
4. Combined Tensile stress vs.
strain curve of 40, 60 and 72.5 grade bar.
5. Show all the points on the
graphs 1, 2, and 3.
12. RESULT
(Students will
fill up this section with their individual outcome/result about the test. Write
the stress values in psi and MPa as shown in Table)
Properties |
40 grade steel |
60 grade steel |
72.5 grade steel |
(500W grade) |
|||
E, psi (MPa) |
|
|
|
p, psi (MPa) |
|
|
|
p, in/in (mm/mm) |
|
|
|
E, psi(MPa) |
|
|
|
E, in/in (mm/mm) |
|
|
|
y, psi(MPa) |
|
|
|
y, in/in (mm/mm) |
|
|
|
u, psi(MPa) |
|
|
|
u, in/in (mm/mm) |
|
|
|
b, psi(MPa) |
|
|
|
b, in/in (mm/mm) |
|
|
|
Ductility
ratio, u / y |
|
|
|
% Elongation |
|
|
|
TS/YS |
|
|
|
EMF, in/in (mm/mm) |
|
|
|
Failure pattern |
|
|
|
Failure type |
|
|
|
13. DISCUSSION
(Discuss on the
results found, graphs, and failure patterns and also compare the results found,
graphs and failure patterns.) Point out the discussion
![]() |
14. ASSIGNMENT
1. Which type of steel have you
tested? What is its carbon content?
2.
What general information is obtained from tensile test
regarding the properties of a material?
3.
Which stress have you calculated: nominal/engineering stress or true stress?
4. What kind of fracture has
occurred in the tensile specimen and why?
5. Which is the most ductile
metal? How much is its elongation?
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